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Physics · 2024

JEE Main · 6 April 2024, Shift 2 · Q60

A wire of cross sectional area A, modulus of elasticity 2 × 10^11 Nm^-2 and length 2 m is stretched between two vertical rigid supports. When a mass…

A wire of cross sectional area A , modulus of elasticity $\displaystyle 2 \times 10^{11} \mathrm{Nm}^{-2}$ and length $\displaystyle 2$ m is stretched between two vertical rigid supports. When a mass of $\displaystyle 2$ kg is suspended at the middle it sags lower from its original position making angle $\displaystyle \theta=\frac{1}{100}$ radian on the points of support. The value of A is $\displaystyle \_\_\_\_$ $\displaystyle \times 10^{-4} \mathrm{~m}^2$ (consider $\displaystyle x \ll \mathrm{~L}$ ). (given : $\displaystyle g=10 \mathrm{~m} / \mathrm{s}^2$ ) Figure: JEE Main Physics 2024, Mechanical Properties of Solids
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.