A 16 Ω wire is bend to form a square loop. A 9 V supply having internal resistance of 1 Ω is connected across one of its sides. The potential drop…

A $\displaystyle 16 \Omega$ wire is bend to form a square loop. A $\displaystyle 9$ V supply having internal resistance of $\displaystyle 1 \Omega$ is connected across one of its sides. The potential drop across the diagonals of the square loop is \_\_\_\_ $\displaystyle \times 10^{-1} \mathrm{~V}$.