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Physics · 2022

JEE Main · 28 June 2022, Shift 2 · Q37

A water drop of radius 1 μ m falls in a situation where the effect of buoyant force is negligible. Co-efficient of viscosity of air is 1.8 × 10^-5…

A water drop of radius $\displaystyle 1 \mu \mathrm{~m}$ falls in a situation where the effect of buoyant force is negligible. Co-efficient of viscosity of air is $\displaystyle 1.8 \times 10^{-5} \mathrm{Nsm}^{-2}$ and its density is negligible as compared to that of water $\displaystyle 10^6 \mathrm{gm}^{-3}$. Terminal velocity of the water drop is : (Take acceleration due to gravity $\displaystyle =10 \mathrm{~ms}^{-2}$ )
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.