Physics · 2022
JEE Main · 24 June 2022, Shift 1 · Q38
A vertical electric field of magnitude 4.9 × 10^5 N / C just prevents a water droplet of a mass 0.1 g from falling. The value of charge on the…
A vertical electric field of magnitude $\displaystyle 4.9 \times 10^5 \mathrm{~N} / \mathrm{C}$ just prevents a water droplet of a mass $\displaystyle 0.1$ g from falling. The value of charge on the droplet will be :
(Given $\displaystyle \mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^2$ )
Official answer
(2)
$\displaystyle 2.0 \times 10^{-9} \mathrm{C}$
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.