Physics · 2022
JEE Main · 26 July 2022, Shift 2 · Q47
A velocity selector consists of electric field E =E k and magnetic field B =B j with B=12 m T. The value of E required for an electron of energy 728…
A velocity selector consists of electric field $\displaystyle \vec{E}=E \hat{k}$ and magnetic field $\displaystyle \vec{B}=B \hat{j}$ with $\displaystyle B=12 m T$. The value of $\displaystyle E$ required for an electron of energy $\displaystyle 728 \mathrm{e} V$ moving along the positive $\displaystyle x$-axis to pass undeflected is :
(Given, mass of electron $\displaystyle =9.1 \times 10^{-31} \mathrm{~kg}$ )
Official answer
(1)
$\displaystyle 192 \mathrm{kVm}^{-1}$
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.