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Physics · 2015
JEE Main · 11 April 2015, Shift 1 · Q2
A vector A is rotated by a small angle Δ θ radians (Δ θ ≪ 1) to get a new vector B. In that case | B - A | is:
A vector $\displaystyle \overrightarrow{\mathrm{A}}$ is rotated by a small angle $\displaystyle \Delta \theta$ radians $\displaystyle (\Delta \theta \ll 1)$ to get a new vector $\displaystyle \overrightarrow{\mathrm{B}}$. In that case $\displaystyle |\overrightarrow{\mathrm{B}}-\overrightarrow{\mathrm{A}}|$ is :
Official answer
(3)
$\displaystyle |\overrightarrow{\mathrm{A}}| \Delta \theta$
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JEE Main 2015 Physics question, with the answer from NTA’s final answer key. Where our answers come from.