Physics · 2022
JEE Main · 28 July 2022, Shift 2 · Q10
A uniform electric field E =(8 m / e ) V / m is created between two parallel plates of length 1 m as shown in figure, (where m = mass of electron and…
A uniform electric field $\displaystyle \mathrm{E}=(8 \mathrm{~m} / \mathrm{e}) \mathrm{V} / \mathrm{m}$ is created between two parallel plates of length $\displaystyle 1$ m as shown in figure, (where $\displaystyle \mathrm{m}=$ mass of electron and $\displaystyle \mathrm{e}=$ charge of electron). An electron enters the field symmetrically between the plates with a speed of $\displaystyle 2 \mathrm{~m} / \mathrm{s}$. The angle of the deviation ( $\displaystyle \theta$ ) of the path of the electron as it comes out of the field will be \_\_\_\_.

Official answer
(2)
$\displaystyle \tan ^{-1}(2)$
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.