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Physics · 2026

JEE Main · 5 April 2026, Shift 1 · Q48

A transverse wave on a string is described by y=3 sin (36 t+0.018 x+π / 4). where x, y are in cm and t in seconds. The least distance between the two…

A transverse wave on a string is described by $\displaystyle y=3 \sin (36 t+0.018 x+\pi / 4)$. where $\displaystyle x, y$ are in cm and $\displaystyle t$ in seconds. The least distance between the two successive crests in the wave is $\displaystyle \_\_\_\_$ cm. (Nearest integer) ( $\displaystyle \pi=3.14$ )
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.