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Physics · 2024

JEE Main · 6 April 2024, Shift 2 · Q39

A total of 48 J heat is given to one mole of helium kept in a cylinder. The temperature of helium increases by 2^° C. The work done by the gas is:…

A total of $\displaystyle 48$ J heat is given to one mole of helium kept in a cylinder. The temperature of helium increases by $\displaystyle 2^{\circ} \mathrm{C}$. The work done by the gas is : Given, $\displaystyle \mathrm{R}=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$.
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.