Physics · 2018
JEE Main · 15 April 2018, Shift 1 · Q9
A thin uniform tube is bent into a circle of radius r in the vertical plane. Equal volumes of two immiscible liquids, whose densities are ρ_1 and…
A thin uniform tube is bent into a circle of radius r in the vertical plane. Equal volumes of two immiscible liquids, whose densities are $\displaystyle \rho_1$ and $\displaystyle \rho_2\left(\rho_1>\rho_2\right)$, fill half the circle. The angle $\displaystyle \theta$ between the radius vector passing through the common interface and the vertical is :
Official answer
(3)
$\displaystyle \theta=\tan ^{-1}\left[\frac{\pi}{2}\left(\frac{\rho_1-\rho_2}{\rho_1+\rho_2}\right)\right]$
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JEE Main 2018 Physics question, with the answer from NTA’s final answer key. Where our answers come from.