Physics · 2026
JEE Main · 6 April 2026, Shift 1 · Q38
A thin half ring of radius 35 cm is uniformly charged with a total charge of Q coulomb. If the magnitude of the electric field at centre of the half…
A thin half ring of radius $\displaystyle 35$ cm is uniformly charged with a total charge of $\displaystyle Q$ coulomb. If the magnitude of the electric field at centre of the half ring is $\displaystyle 100 \mathrm{~V} / \mathrm{m}$, then the value of $\displaystyle Q$ is $\displaystyle \_\_\_\_$ nC .
( $\displaystyle \epsilon_0=8.85 \times 10^{-12} \mathrm{C}^2 / \mathrm{Nm}^2$ and $\displaystyle \pi=3.14$ )
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 2.14$
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.