Physics · 2019
JEE Main · 10 January 2019, Shift 1 · Q12
A string of length 1 m and mass 5 g is fixed at both ends. The tension in the string is 8.0 N. The string is set into vibration using an external…
A string of length $\displaystyle 1$ m and mass $\displaystyle 5$ g is fixed at both ends. The tension in the string is $\displaystyle 8.0$ N. The string is set into vibration using an external vibrator of frequency $\displaystyle 100$ Hz . The separation between successive nodes on the string is close to :
Official answer
(3)
20.$\displaystyle 0$ cm
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.