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Physics · 2020
JEE Main · 7 January 2020, Shift 2 · Q9
A stationary observer receives sound from two identical tuning forks, one of which approaches and the other one recedes with the same speed (much…
A stationary observer receives sound from two identical tuning forks, one of which approaches and the other one recedes with the same speed (much less than the speed of sound). The observer hears $\displaystyle 2$ beats/ sec. The oscillation frequency of each tuning fork is $\displaystyle \nu_0=1400 \mathrm{~Hz}$ and the velocity of sound in air is $\displaystyle 350$ m/s. The speed of each tuning fork is close to :
Official answer
(3)
$\displaystyle \frac{1}{4} \mathrm{~m} / \mathrm{s}$
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.