Physics · 2026
JEE Main · 24 January 2026, Shift 2 · Q48
A soap bubble of surface tension 0.04 N / m is blown to a diameter of 7 cm. If (15000-x) μ J of work is done in blowing it further to make its…
A soap bubble of surface tension $\displaystyle 0.04 \mathrm{~N} / \mathrm{m}$ is blown to a diameter of $\displaystyle 7$ cm . If $\displaystyle (15000-x) \mu \mathrm{J}$ of work is done in blowing it further to make its diameter $\displaystyle 14$ cm , then the value of $\displaystyle x$ is $\displaystyle \_\_\_\_$.
( $\displaystyle \pi=22 / 7$ )
Official answer
From NTA’s final answer key for this paper.
11304
More from Surface Tension and Viscosity
- Eight mercury drops, each of radius r, coalesce to form a bigger drop. The surface energy released in this process is ____. (S is the surface tension…2026
- The surface tension of a soap bubble is 0.03 N / m. The work done in increasing the diameter of bubble from 2 cm to 6 cm is α π × 10^-4 J. The value…2026
- If an air bubble of diameter 2 mm rises steadily through a liquid of density 2000 kg / m^3 at a rate of 0.5 cm/s, then the coefficient of viscosity…2026
- The surface tension of a soap solution is 3.5 × 10^-2 N / m. The work required to increase the radius of a soap bubble from 1 cm to 2 cm is α × 10^-6…2026
- A liquid drop of diameter 2 mm breaks into 512 droplets. The change in surface energy is α × 10^-6 J. The value of α is ____. (Take surface tension…2026
- A spherical liquid drop of radius R acquires the terminal velocity v_1 when falls through a gas of viscosity η. Now the drop is broken into 64…2026
JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.