Physics · 2019
JEE Main · 10 April 2019, Shift 2 · Q16
A simple pendulum of length L is placed between the plates of a parallel plate capacitor having electric field E, as shown in figure. Its bob has…
A simple pendulum of length L is placed between the plates of a parallel plate capacitor having electric field E, as shown in figure. Its bob has mass m and charge q. The time period of the pendulum is given by :
Official answer
(3)
$\displaystyle 2 \pi \sqrt{\frac{L}{\sqrt{g^2+\left(\dfrac{q E}{m}\right)^2}}}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.