Physics · 2019
JEE Main · 11 January 2019, Shift 2 · Q13
A simple pendulum of length 1 m is oscillating with an angular frequency 10 rad/s. The support of the pendulum starts oscillating up and down with a…
A simple pendulum of length $\displaystyle 1$ m is oscillating with an angular frequency $\displaystyle 10$ rad/s. The support of the pendulum starts oscillating up and down with a small angular frequency of $\displaystyle 1$ rad/s and an amplitude of $\displaystyle 10^{-2} \mathrm{~m}$. The relative change in the angular frequency of the pendulum is best given by :
Official answer
(2)
$\displaystyle 10^{-3} \mathrm{rad} / \mathrm{s}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.