Physics · 2024
JEE Main · 30 January 2024, Shift 1 · Q43
A series L.R circuit connected with an ac source E =(25 sin 1000 t ) V has a power factor of 1/(√ 2). If the source of emf is changed to E =(20 sin…
A series L.R circuit connected with an ac source $\displaystyle \mathrm{E}=(25 \sin 1000 \mathrm{t}) \mathrm{V}$ has a power factor of $\displaystyle \frac{1}{\sqrt{2}}$. If the source of emf is changed to $\displaystyle \mathrm{E}=(20 \sin 2000 \mathrm{t}) \mathrm{V}$, the new power factor of the circuit will be :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \frac{1}{\sqrt{5}}$
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.