A proton with a kinetic energy of 2.0 eV moves into a region of uniform magnetic field of magnitude (π)/2 × 10^-3 T. The angle between the direction…

A proton with a kinetic energy of $\displaystyle 2.0$ eV moves into a region of uniform magnetic field of magnitude $\displaystyle \frac{\pi}{2} \times 10^{-3} \mathrm{~T}$. The angle between the direction of magnetic field and velocity of proton is $\displaystyle 60^{\circ}$. The pitch of the helical path taken by the proton is $\displaystyle \_\_\_\_$ cm . (Take, mass of proton $\displaystyle =1.6 \times 10^{-27} \mathrm{~kg}$ and Charge on proton $\displaystyle =1.6 \times 10^{-19} \mathrm{C}$ ).