Physics · 2015
JEE Main · 10 April 2015, Shift 1 · Q19
A proton (mass m) accelerated by a potential difference V flies through a uniform transverse magnetic field B. The field occupies a region of space…
A proton (mass m) accelerated by a potential difference V flies through a uniform transverse magnetic field B. The field occupies a region of space by width ' d '. If ' $\displaystyle \alpha$ ' be the angle of deviation of proton from initial direction of motion (see figure), the value of $\displaystyle \sin \alpha$ will be :
Official answer
(3)
$\displaystyle B d \sqrt{\frac{q}{2 m V}}$
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JEE Main 2015 Physics question, with the answer from NTA’s final answer key. Where our answers come from.