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Physics · 2013
JEE Main 2013 · 2013-04-07 Offline · Q40
A projectile is given an initial velocity of ( i +2 j ) m / s, where i is along the ground and j is along the vertical. If g =10 m / s^2, the…
A projectile is given an initial velocity of $\displaystyle (\hat{i}+2 \hat{j}) \mathrm{m} / \mathrm{s}$, where $\displaystyle \hat{i}$ is along the ground and $\displaystyle \hat{j}$ is along the vertical. If $\displaystyle \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$, the equation of its trajectory is :
Official answer
(3)
$\displaystyle y=2 x-5 x^2$
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JEE Main 2013 Physics question, with the answer from NTA’s final answer key. Where our answers come from.