Physics · 2019
JEE Main · 12 April 2019, Shift 2 · Q21
A plane electromagnetic wave having a frequency v=23.9 GHz propagates along the positive z -direction in free space. The peak value of the Electric…
A plane electromagnetic wave having a frequency $\displaystyle v=23.9 \mathrm{GHz}$ propagates along the positive $\displaystyle z$-direction in free space. The peak value of the Electric Field is $\displaystyle 60 \mathrm{~V} / \mathrm{m}$. Which among the following is the acceptable magnetic field component in the electromagnetic wave ?
Official answer
(2)
$\displaystyle \overrightarrow{\mathrm{B}}=2 \times 10^{-7} \sin \left(0.5 \times 10^3 z-1.5 \times 10^{11} \mathrm{t}\right) \hat{i}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.