Physics · 2023
JEE Main · 10 April 2023, Shift 1 · Q35
A physical quantity P is given as P=(a^2 b^3)/(c √ d) The percentage error in the measurement of a, b, c and d are 1%, 2%, 3% and 4% respectively.…
A physical quantity P is given as
$$P=\frac{a^2 b^3}{c \sqrt{d}}
$$
The percentage error in the measurement of $\displaystyle a, b, c$ and $\displaystyle d$ are $\displaystyle 1$%, $\displaystyle 2$%, $\displaystyle 3$% and $\displaystyle 4$% respectively. The percentage error in the measurement of quantity P will be
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 13$%
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.