Physics · 2019
JEE Main · 11 January 2019, Shift 2 · Q12
A pendulum is executing simple harmonic motion and its maximum kinetic energy is K_1. If the length of the pendulum is doubled and it performs simple…
A pendulum is executing simple harmonic motion and its maximum kinetic energy is $\displaystyle \mathrm{K}_1$. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is $\displaystyle \mathrm{K}_2$. Then :
Official answer
(3)
$\displaystyle \mathrm{K}_2=\frac{\mathrm{K}_1}{2}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.