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Physics · 2026

JEE Main · 28 January 2026, Shift 2 · Q30

A particle starts moving from time t=0 and its coordinate is given as x(t)=4 t^3-3 t A. The particle returns to its original position (origin) 0.866…

A particle starts moving from time $\displaystyle t=0$ and its coordinate is given as $\displaystyle x(t)=4 t^3-3 t$ A. The particle returns to its original position (origin) $\displaystyle 0.866$ units later B. The particle is $\displaystyle 1$ unit away from origin at its turning point C. Acceleration of the particle is non-negative D. The particle is $\displaystyle 0.5$ units away from origin at its turning point E. Particle never turns back as acceleration is non-negative Choose the correct answer from the options given below :
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.