Physics · 2021
JEE Main · 18 March 2021, Shift 1 · Q25
A particle performs simple harmonic motion with a period of 2 second. The time taken by the particle to cover a displacement equal to half of its…
A particle performs simple harmonic motion with a period of $\displaystyle 2$ second. The time taken by the particle to cover a displacement equal to half of its amplitude from the mean position is $\displaystyle \frac{1}{\mathrm{a}} \mathrm{s}$.
The value of 'a' to the nearest integer is \_\_\_\_.
Official answer
6
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.