Physics · 2021
JEE Main · 31 August 2021, Shift 1 · Q22
A particle of mass 1 kg is hanging from a spring of force constant 100 Nm^-1. The mass is pulled slightly downward and released so that it executes…
A particle of mass $\displaystyle 1$ kg is hanging from a spring of force constant $\displaystyle 100 \mathrm{Nm}^{-1}$. The mass is pulled slightly downward and released so that it executes free simple harmonic motion with time period T. The time when the kinetic energy and potential energy of the system will become equal, is $\displaystyle \frac{\mathrm{T}}{x}$. The value of $\displaystyle x$ is \_\_\_\_.
Official answer
8
More from Simple Harmonic Motion
- For particle P revolving round the centre O with radius of circular path r and angular velocity ω, as shown in below figure, the projection of OP on…2023
- Two identical springs of spring constant ' 2 k ' are attached to a block of mass m and to fixed support (see figure). When the mass is displaced from…2021
- A simple pendulum doing small oscillations at a place R height above earth surface has time period of T_1=4 s. T_2 would be it's time period if it is…2024
- In the given figure, a body of mass M is held between two massless springs, on a smooth inclined plane. The free ends of the springs are attached to…2021
- For what value of displacement the kinetic energy and potential energy of a simple harmonic oscillation become equal?2021
- A piece of wood has dimensions ℓ, b and h. Its relative density is ' d '. It is floating in water such that the side ' h ' is vertical. If it is…2021
- A mass m is suspended from a spring of negligible mass and the system oscillates with a frequency f_1. The frequency of oscillations if a mass 9 m is…2024
- A simple pendulum with length 100 cm and bob of mass 250 g is executing S.H.M. of amplitude 10 cm. The maximum tension in the string is found to be…2023
JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.