Physics · 2020
JEE Main · 6 September 2020, Shift 1 · Q12
A particle of charge q and mass m is moving with a velocity -v i (v ≠ 0) towards a large screen placed in the Y-Z plane at a distance d. If there is…
A particle of charge q and mass m is moving with a velocity $\displaystyle -v \hat{i}(v \neq 0)$ towards a large screen placed in the Y-Z plane at a distance d. If there is a magnetic field $\displaystyle \overrightarrow{\mathrm{B}}=\mathrm{B}_0 \hat{k}$, the minimum value of $\displaystyle v$ for which the particle will not hit the screen is :
Official answer
(1)
$\displaystyle \frac{\mathrm{qdB}_0}{\mathrm{~m}}$
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.