Physics · 2013
JEE Main · 23 April 2013, Shift 1 · Q18
A particle of charge 16 × 10^-16 C moving with velocity 10 ms^-1 along x -axis enters a region where magnetic field of induction → B is along the y…
A particle of charge $\displaystyle 16 \times 10^{-16} \mathrm{C}$ moving with velocity $\displaystyle 10 \mathrm{~ms}^{-1}$ along $\displaystyle x$-axis enters a region where magnetic field of induction
→
B is along the $\displaystyle y$-axis and an electric field of magnitude $\displaystyle 10^4 \mathrm{Vm}^{-1}$ is along the negative $\displaystyle z$-axis. If the charged particle continues moving along $\displaystyle x$-axis, the magnitude of $\displaystyle \vec{B}$ is :
Official answer
(3)
$\displaystyle 1 \times 10^3 \mathrm{~Wb} \mathrm{~m}^{-2}$
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JEE Main 2013 Physics question, with the answer from NTA’s final answer key. Where our answers come from.