Physics · 2026
JEE Main · 2 April 2026, Shift 1 · Q31
A particle is rotating in a circular path and at any instant its motion can be described as θ=(5 t^4)/40-t^3/3. The angular acceleration of the…
A particle is rotating in a circular path and at any instant its motion can be described as $\displaystyle \theta=\frac{5 t^4}{40}-\frac{t^3}{3}$. The angular acceleration of the particle after $\displaystyle 10$ seconds is $\displaystyle \_\_\_\_$ $\displaystyle \mathrm{rad} / \mathrm{s}^2$.
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 130$
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.