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Physics · 2018
JEE Main 2018 · 2018-04-08 Offline · Q4
A particle is moving in a circular path of radius a under the action of an attractive potential U =-k/(2 r^2). Its total energy is:
A particle is moving in a circular path of radius a under the action of an attractive potential $\displaystyle \mathrm{U}=-\frac{\mathrm{k}}{2 \mathrm{r}^2}$. Its total energy is :
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