A particle is moving along the x -axis with its coordinate with time ' t ' given by x( t )=10+8 t -3 t^2. Another particle is moving along the y…

A particle is moving along the $\displaystyle x$-axis with its coordinate with time ' $\displaystyle t$ ' given by $\displaystyle x(\mathrm{t})=10+8 \mathrm{t}-3 \mathrm{t}^2$. Another particle is moving along the $\displaystyle y$-axis with its coordinate as a function of time given by $\displaystyle y(t)=5-8 t^3$. At $\displaystyle \mathrm{t}=1 \mathrm{~s}$, the speed of the second particle as measured in the frame of the first particle is given as $\displaystyle \sqrt{v}$. Then $\displaystyle v$ (in m/s) is \_\_\_\_.