Physics · 2019
JEE Main · 9 January 2019, Shift 2 · Q13
A particle is executing simple harmonic motion (SHM) of amplitude A, along the x -axis, about x=0. When its potential Energy (PE) equals kinetic…
A particle is executing simple harmonic motion (SHM) of amplitude A, along the $\displaystyle x$-axis, about $\displaystyle x=0$. When its potential Energy (PE) equals kinetic energy (KE), the position of the particle will be :
Official answer
(3)
$\displaystyle \frac{\mathrm{A}}{\sqrt{2}}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.