Physics · 2024
JEE Main · 6 April 2024, Shift 1 · Q52
A particle is doing simple harmonic motion of amplitude 0.06 m and time period 3.14 s. The maximum velocity of the particle is ____ cm / s.
A particle is doing simple harmonic motion of amplitude $\displaystyle 0.06$ m and time period $\displaystyle 3.14$ s. The maximum velocity of the particle is $\displaystyle \_\_\_\_$ $\displaystyle \mathrm{cm} / \mathrm{s}$.
Official answer
From NTA’s final answer key for this paper.
12
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