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Physics · 2021

JEE Main · 27 July 2021, Shift 2 · Q29

A particle executes simple harmonic motion represented by displacement function as x(t)=A sin (ω t+φ) If the position and velocity of the particle at…

A particle executes simple harmonic motion represented by displacement function as $$x(t)=A \sin (\omega t+\phi) $$ If the position and velocity of the particle at $\displaystyle \mathrm{t}=0 \mathrm{~s}$ are $\displaystyle 2$ cm and $\displaystyle 2 \omega \mathrm{~cm} \mathrm{~s}^{-1}$ respectively, then its amplitude is $\displaystyle x \sqrt{2} \mathrm{~cm}$ where the value of $\displaystyle x$ is \_\_\_\_.
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