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Physics · 2021

JEE Main · 26 February 2021, Shift 2 · Q29

A particle executes S.H.M. with amplitude 'a' and time period 'T'. The displacement of the particle when its speed is half of maximum speed is (√ x…

A particle executes S.H.M. with amplitude 'a' and time period 'T'. The displacement of the particle when its speed is half of maximum speed is $\displaystyle \frac{\sqrt{x} \mathrm{a}}{2}$. The value of $\displaystyle x$ is \_\_\_\_.
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.