Physics · 2019
JEE Main · 10 January 2019, Shift 1 · Q21
A magnet of total magnetic moment 10^-2 i A - m^2 is placed in a time varying magnetic field, B i ( cos ω t) where B =1 Tesla and ω=0.125 rad / s.…
A magnet of total magnetic moment $\displaystyle 10^{-2} \hat{i} \mathrm{~A}-\mathrm{m}^2$ is placed in a time varying
magnetic field, $\displaystyle \mathrm{B} \hat{i}(\cos \omega t)$ where $\displaystyle \mathrm{B}=1$ Tesla and $\displaystyle \omega=0.125 \mathrm{rad} / \mathrm{s}$. The work done for reversing the direction of the magnetic moment at $\displaystyle \mathrm{t}=1$ second, is :
Official answer
No correct option: NTA dropped this question in its final answer key.
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.