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Physics · 2020
JEE Main · 7 January 2020, Shift 1 · Q24
A loop ABCDEFA of straight edges has six corner points A (0,0,0), B (5,0,0), C (5,5,0), D(0, 5, 0), E(0, 5, 5) and F(0, 0, 5). The magnetic field in…
A loop ABCDEFA of straight edges has six corner points $\displaystyle \mathrm{A}(0,0,0), \mathrm{B}(5,0,0), \mathrm{C}(5,5,0)$, D($\displaystyle 0$, $\displaystyle 5$, $\displaystyle 0$), E($\displaystyle 0$, $\displaystyle 5$, $\displaystyle 5$) and F($\displaystyle 0$, $\displaystyle 0$, $\displaystyle 5$). The magnetic field in this region is $\displaystyle \overrightarrow{\mathrm{B}}=(3 \hat{i}+4 \hat{k}) \mathrm{T}$. The quantity of flux through the loop ABCDEFA (in Wb) is
\_\_\_\_.
Official answer
175
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.