Physics · 2016
JEE Main · 10 April 2016, Shift 1 · Q16
A fighter plane of length 20 m, wing span (distance from tip of one wing to the tip of the other wing) of 15 m and height 5 m is flying towards east…
A fighter plane of length $\displaystyle 20$ m, wing span (distance from tip of one wing to the tip of the other wing) of $\displaystyle 15$ m and height $\displaystyle 5$ m is flying towards east over Delhi. Its speed is $\displaystyle 240 \mathrm{~ms}^{-1}$. The earth's magnetic field over Delhi is $\displaystyle 5 \times 10^{-5} \mathrm{~T}$ with the declination angle ~$\displaystyle 0$° and dip of $\displaystyle \theta$ such that $\displaystyle \sin \theta=\frac{2}{3}$. If the voltage developed is $\displaystyle V_B$ between the lower and upper side of the plane and $\displaystyle V_W$ between the tips of the wings then $\displaystyle V_B$ and $\displaystyle V_W$ are close to :
Official answer
(2)
$\displaystyle V_B=45 m V ; V_W=120 m V$ with left side of pilot at higher voltage
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JEE Main 2016 Physics question, with the answer from NTA’s final answer key. Where our answers come from.