Physics · 2022
JEE Main · 30 June 2022, Shift 1 · Q43
A cyclotron is working at a frequency of 10 MHz. If the radius of its dees is 60 cm. The maximum kinetic energy of accelerated proton will be: (Take:…
A cyclotron is working at a frequency of $\displaystyle 10$ MHz . If the radius of its dees is $\displaystyle 60$ cm. The maximum kinetic energy of accelerated proton will be :
(Take : $\displaystyle \mathrm{e}=1.6 \times 10^{-19} \mathrm{C}, \mathrm{m}_{\mathrm{p}}=1.67 \times 10^{-27} \mathrm{~kg}$ )
Official answer
(1)
7.$\displaystyle 4$ MeV
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.