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Physics · 2025

JEE Main · 24 January 2025, Shift 1 · Q49

A current of 5A exists in a square loop of side 1/(√ 2) m. Then the magnitude of the magnetic field B at the centre of the square loop will be p ×…

A current of 5A exists in a square loop of side $\displaystyle \frac{1}{\sqrt{2}} \mathrm{~m}$. Then the magnitude of the magnetic field B at the centre of the square loop will be $\displaystyle \mathrm{p} \times 10^{-6} \mathrm{~T}$. where, value of p is $\displaystyle \_\_\_\_$. $\displaystyle \left[\right.$ Take $\displaystyle \left.\mu_0=4 \pi \times 10^{-7} \mathrm{TmA}^{-1}\right]$.
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JEE Main 2025 Physics question, with the answer from NTA’s final answer key. Where our answers come from.