Physics · 2019
JEE Main · 10 January 2019, Shift 2 · Q17
A current of 2 mA was passed through an unknown resistor which dissipated a power of 4.4 W. Dissipated power when an ideal power supply of 11 V is…
A current of $\displaystyle 2$ mA was passed through an unknown resistor which dissipated a power of $\displaystyle 4.4$ W. Dissipated power when an ideal power supply of $\displaystyle 11$ V is connected across it is :
Official answer
(3)
$\displaystyle 11 \times 10^{-5} \mathrm{~W}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.