Physics · 2018
JEE Main · 15 April 2018, Shift 2 · Q18
A current of 1 A is flowing on the sides of an equilateral triangle of side 4.5 × 10^-2 m. The magnetic field at the centre of the triangle will be:
A current of $\displaystyle 1$ A is flowing on the sides of an equilateral triangle of side $\displaystyle 4.5 \times 10^{-2} \mathrm{~m}$. The magnetic field at the centre of the triangle will be :
Official answer
(4)
$\displaystyle 4 \times 10^{-5} \mathrm{~Wb} / \mathrm{m}^2$
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JEE Main 2018 Physics question, with the answer from NTA’s final answer key. Where our answers come from.