Physics · 2023
JEE Main · 30 January 2023, Shift 2 · Q13
A current carrying rectangular loop P Q R S is made of uniform wire. The length P R=Q S=5 cm and P Q=R S=100 cm. If ammeter current reading changes…
A current carrying rectangular loop $\displaystyle P Q R S$ is made of uniform wire. The length $\displaystyle P R=Q S=5 \mathrm{~cm}$ and $\displaystyle P Q=R S=100 \mathrm{~cm}$. If ammeter current reading changes from I to $\displaystyle 2 I$, the ratio of magnetic forces per unit length on the wire $\displaystyle P Q$ due to wire $\displaystyle R S$ in the two cases respectively $\displaystyle \left(f_{P Q}^I: f_{P Q}^{2 I}\right)$ is:
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 1$ : $\displaystyle 4$
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.