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Physics · 2023

JEE Main · 1 February 2023, Shift 2 · Q26

A cubical volume is bounded by the surfaces x=0, x= a, y=0, y= a, z=0, z= a. The electric field in the region is given by E = E_0 x i. Where E_0=4 ×…

A cubical volume is bounded by the surfaces $\displaystyle x=0, x=\mathrm{a}, y=0, y=\mathrm{a}, z=0, z=\mathrm{a}$. The electric field in the region is given by $\displaystyle \overrightarrow{\mathrm{E}}=\mathrm{E}_0 x \hat{i}$. Where $\displaystyle \mathrm{E}_0=4 \times 10^4 \mathrm{NC}^{-1} \mathrm{~m}^{-1}$. If $\displaystyle \mathrm{a}=2 \mathrm{~cm}$, the charge contained in the cubical volume is $\displaystyle \mathrm{Q} \times 10^{-14} \mathrm{C}$. The value of Q is $\displaystyle \_\_\_\_$. Take $\displaystyle \epsilon_0=9 \times 10^{-12} \mathrm{C}^2 / \mathrm{Nm}^2$ )
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.