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Physics · 2014

JEE Main 2014 · 2014-04-06 Offline · Q19

A conductor lies along the z-axis at -1.5 ≤ z <1.5 m and carries a fixed current of 10.0 A in - a_z direction (see figure). For a field B =3.0 ×…

A conductor lies along the z-axis at $\displaystyle -1.5 \leq \mathrm{z}<1.5 \mathrm{~m}$ and carries a fixed current of $\displaystyle 10.0$ A in - $\displaystyle \hat{\mathrm{a}}_{\mathrm{z}}$ direction (see figure). For a field $\displaystyle \overrightarrow{\mathrm{B}}=3.0 \times 10^{-4} \mathrm{e}^{-0.2 x} \hat{\mathrm{a}}_y \mathrm{~T}$, find the power required to move the conductor at constant speed to $\displaystyle x=2.0 \mathrm{~m}, y=0 \mathrm{~m}$ in $\displaystyle 5 \times 10^{-3} \mathrm{~s}$. Assume parallel motion along the $\displaystyle x$-axis. Figure: JEE Main Physics 2014, Magnetic Field and Forces
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JEE Main 2014 Physics question, with the answer from NTA’s final answer key. Where our answers come from.