SolveIt is under development
SolveItJEE Main
Physics · 2019

JEE Main · 9 January 2019, Shift 1 · Q22

A conducting circular loop made of a thin wire, has area 3.5 × 10^-3 m^2 and resistance 10 Ω. It is placed perpendicular to a time dependent magnetic…

A conducting circular loop made of a thin wire, has area $\displaystyle 3.5 \times 10^{-3} \mathrm{~m}^2$ and resistance $\displaystyle 10 \Omega$. It is placed perpendicular to a time dependent magnetic field $\displaystyle \mathrm{B}(\mathrm{t})=(0.4 \mathrm{~T}) \sin (50 \pi \mathrm{t})$. The field is uniform in space. Then the net charge flowing through the loop during $\displaystyle \mathrm{t}=0 \mathrm{~s}$ and $\displaystyle \mathrm{t}=10 \mathrm{~ms}$ is close to :
ShareWhatsAppTelegram

More from Electromagnetic Induction

JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.