Physics · 2022
JEE Main · 27 July 2022, Shift 2 · Q40
A charge of 4 μ C is to be divided into two. The distance between the two divided charges is constant. The magnitude of the divided charges so that…
A charge of $\displaystyle 4 \mu \mathrm{C}$ is to be divided into two. The distance between the two divided charges is constant. The magnitude of the divided charges so that the force between them is maximum, will be :
Official answer
(2)
$\displaystyle 2 \mu \mathrm{C} \text { and } 2 \mu \mathrm{C}$
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.