Physics · 2023
JEE Main · 24 January 2023, Shift 2 · Q5
A body of mass 200g is tied to a spring of spring constant 12.5 N / m, while the other end of spring is fixed at point O. If the body moves about O…
A body of mass 200g is tied to a spring of spring constant $\displaystyle 12.5 \mathrm{~N} / \mathrm{m}$, while the other end of spring is fixed at point O . If the body moves about O in a circular path on a smooth horizontal surface with constant angular speed $\displaystyle 5 \mathrm{rad} / \mathrm{s}$. Then the ratio of extension in the spring to its natural length will be :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 2$:$\displaystyle 3$
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.