Physics · 2026
JEE Main · 21 January 2026, Shift 2 · Q31
A body of mass 2 kg is moving along x -direction such that its displacement as function of time is given by x(t)=α t^2+β t+γ m, where α=1 m / s^2,…
A body of mass $\displaystyle 2$ kg is moving along $\displaystyle x$-direction such that its displacement as function of time is given by $\displaystyle x(t)=\alpha t^2+\beta t+\gamma \mathrm{m}$, where $\displaystyle \alpha=1 \mathrm{~m} / \mathrm{s}^2, \beta=1 \mathrm{~m} / \mathrm{s}$ and $\displaystyle \gamma=1 \mathrm{~m}$. The work done on the body during the time interval $\displaystyle t=2 \mathrm{~s}$ to $\displaystyle t=3 \mathrm{~s}$, is $\displaystyle \_\_\_\_$J.
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 24$
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.