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Physics · 2026

JEE Main · 24 January 2026, Shift 2 · Q32

10 mole of an ideal gas is undergoing the process shown in the figure. The heat involved in the process from P_1 to P_2 is α Joule ( P_1=21.7 Pa and…

$\displaystyle 10$ mole of an ideal gas is undergoing the process shown in the figure. The heat involved in the process from $\displaystyle P_1$ to $\displaystyle P_2$ is $\displaystyle \alpha$ Joule ( $\displaystyle P_1=21.7 \mathrm{~Pa}$ and $\displaystyle P_2=30 \mathrm{~Pa}, \mathrm{C}_v=21 \mathrm{~J} / \mathrm{K} . \mathrm{mol}, R=8.3 \mathrm{~J} / \mathrm{mol} . \mathrm{K}$ ). The value of $\displaystyle \alpha$ is $\displaystyle \_\_\_\_$. Figure: JEE Main Physics 2026, Thermodynamics
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.